Integrand size = 32, antiderivative size = 103 \[ \int \frac {\sin ^3(c+d x) (A-A \sin (c+d x))}{(a+a \sin (c+d x))^3} \, dx=\frac {4 A x}{a^3}+\frac {A \cos (c+d x)}{a^3 d}+\frac {2 A \cos (c+d x)}{5 a^3 d (1+\sin (c+d x))^3}-\frac {31 A \cos (c+d x)}{15 a^3 d (1+\sin (c+d x))^2}+\frac {104 A \cos (c+d x)}{15 a^3 d (1+\sin (c+d x))} \]
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Time = 0.16 (sec) , antiderivative size = 103, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.125, Rules used = {3045, 2718, 2729, 2727} \[ \int \frac {\sin ^3(c+d x) (A-A \sin (c+d x))}{(a+a \sin (c+d x))^3} \, dx=\frac {A \cos (c+d x)}{a^3 d}+\frac {104 A \cos (c+d x)}{15 a^3 d (\sin (c+d x)+1)}-\frac {31 A \cos (c+d x)}{15 a^3 d (\sin (c+d x)+1)^2}+\frac {2 A \cos (c+d x)}{5 a^3 d (\sin (c+d x)+1)^3}+\frac {4 A x}{a^3} \]
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Rule 2718
Rule 2727
Rule 2729
Rule 3045
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {4 A}{a^3}-\frac {A \sin (c+d x)}{a^3}-\frac {2 A}{a^3 (1+\sin (c+d x))^3}+\frac {7 A}{a^3 (1+\sin (c+d x))^2}-\frac {9 A}{a^3 (1+\sin (c+d x))}\right ) \, dx \\ & = \frac {4 A x}{a^3}-\frac {A \int \sin (c+d x) \, dx}{a^3}-\frac {(2 A) \int \frac {1}{(1+\sin (c+d x))^3} \, dx}{a^3}+\frac {(7 A) \int \frac {1}{(1+\sin (c+d x))^2} \, dx}{a^3}-\frac {(9 A) \int \frac {1}{1+\sin (c+d x)} \, dx}{a^3} \\ & = \frac {4 A x}{a^3}+\frac {A \cos (c+d x)}{a^3 d}+\frac {2 A \cos (c+d x)}{5 a^3 d (1+\sin (c+d x))^3}-\frac {7 A \cos (c+d x)}{3 a^3 d (1+\sin (c+d x))^2}+\frac {9 A \cos (c+d x)}{a^3 d (1+\sin (c+d x))}-\frac {(4 A) \int \frac {1}{(1+\sin (c+d x))^2} \, dx}{5 a^3}+\frac {(7 A) \int \frac {1}{1+\sin (c+d x)} \, dx}{3 a^3} \\ & = \frac {4 A x}{a^3}+\frac {A \cos (c+d x)}{a^3 d}+\frac {2 A \cos (c+d x)}{5 a^3 d (1+\sin (c+d x))^3}-\frac {31 A \cos (c+d x)}{15 a^3 d (1+\sin (c+d x))^2}+\frac {20 A \cos (c+d x)}{3 a^3 d (1+\sin (c+d x))}-\frac {(4 A) \int \frac {1}{1+\sin (c+d x)} \, dx}{15 a^3} \\ & = \frac {4 A x}{a^3}+\frac {A \cos (c+d x)}{a^3 d}+\frac {2 A \cos (c+d x)}{5 a^3 d (1+\sin (c+d x))^3}-\frac {31 A \cos (c+d x)}{15 a^3 d (1+\sin (c+d x))^2}+\frac {104 A \cos (c+d x)}{15 a^3 d (1+\sin (c+d x))} \\ \end{align*}
Time = 2.19 (sec) , antiderivative size = 155, normalized size of antiderivative = 1.50 \[ \int \frac {\sin ^3(c+d x) (A-A \sin (c+d x))}{(a+a \sin (c+d x))^3} \, dx=-\frac {A \sec (c+d x) \left (-120 \arcsin \left (\frac {\sqrt {a (1+\sin (c+d x))}}{\sqrt {2} \sqrt {a}}\right ) \left (\cos \left (\frac {1}{2} (c+d x)\right )+\sin \left (\frac {1}{2} (c+d x)\right )\right )^4 \sqrt {1-\sin (c+d x)} \sqrt {a (1+\sin (c+d x))}+\sqrt {a} \left (-94-128 \sin (c+d x)+73 \sin ^2(c+d x)+134 \sin ^3(c+d x)+15 \sin ^4(c+d x)\right )\right )}{15 a^{7/2} d (1+\sin (c+d x))^2} \]
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Time = 0.93 (sec) , antiderivative size = 115, normalized size of antiderivative = 1.12
method | result | size |
derivativedivides | \(\frac {16 A \left (\frac {1}{5 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{5}}-\frac {1}{2 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{4}}+\frac {1}{12 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{3}}+\frac {3}{8 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{2}}+\frac {1}{2 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+2}+\frac {1}{8+8 \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}+\frac {\arctan \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2}\right )}{d \,a^{3}}\) | \(115\) |
default | \(\frac {16 A \left (\frac {1}{5 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{5}}-\frac {1}{2 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{4}}+\frac {1}{12 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{3}}+\frac {3}{8 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{2}}+\frac {1}{2 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+2}+\frac {1}{8+8 \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}+\frac {\arctan \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2}\right )}{d \,a^{3}}\) | \(115\) |
risch | \(\frac {4 A x}{a^{3}}+\frac {A \,{\mathrm e}^{i \left (d x +c \right )}}{2 a^{3} d}+\frac {A \,{\mathrm e}^{-i \left (d x +c \right )}}{2 a^{3} d}+\frac {2 A \left (435 i {\mathrm e}^{3 i \left (d x +c \right )}+135 \,{\mathrm e}^{4 i \left (d x +c \right )}-385 i {\mathrm e}^{i \left (d x +c \right )}-605 \,{\mathrm e}^{2 i \left (d x +c \right )}+104\right )}{15 d \,a^{3} \left ({\mathrm e}^{i \left (d x +c \right )}+i\right )^{5}}\) | \(116\) |
parallelrisch | \(\frac {A \left (120 d x \sin \left (\frac {5 d x}{2}+\frac {5 c}{2}\right )-600 d x \sin \left (\frac {3 d x}{2}+\frac {3 c}{2}\right )+600 d x \cos \left (\frac {3 d x}{2}+\frac {3 c}{2}\right )+120 d x \cos \left (\frac {5 d x}{2}+\frac {5 c}{2}\right )-1200 d x \sin \left (\frac {d x}{2}+\frac {c}{2}\right )-1200 d x \cos \left (\frac {d x}{2}+\frac {c}{2}\right )+15 \sin \left (\frac {7 d x}{2}+\frac {7 c}{2}\right )-95 \sin \left (\frac {5 d x}{2}+\frac {5 c}{2}\right )-1575 \sin \left (\frac {3 d x}{2}+\frac {3 c}{2}\right )+305 \cos \left (\frac {3 d x}{2}+\frac {3 c}{2}\right )+471 \cos \left (\frac {5 d x}{2}+\frac {5 c}{2}\right )+15 \cos \left (\frac {7 d x}{2}+\frac {7 c}{2}\right )-1465 \sin \left (\frac {d x}{2}+\frac {c}{2}\right )-2295 \cos \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{30 d \,a^{3} \left (\sin \left (\frac {5 d x}{2}+\frac {5 c}{2}\right )-5 \sin \left (\frac {3 d x}{2}+\frac {3 c}{2}\right )+5 \cos \left (\frac {3 d x}{2}+\frac {3 c}{2}\right )+\cos \left (\frac {5 d x}{2}+\frac {5 c}{2}\right )-10 \cos \left (\frac {d x}{2}+\frac {c}{2}\right )-10 \sin \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}\) | \(242\) |
norman | \(\frac {\frac {164 A \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{3 a d}+\frac {284 A x \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{a}+\frac {188 A}{15 a d}+\frac {40 A \left (\tan ^{11}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{a d}+\frac {8 A \left (\tan ^{12}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{a d}+\frac {204 A x \left (\tan ^{9}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{a}+\frac {20 A x \left (\tan ^{12}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{a}+\frac {2032 A \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{15 a d}+\frac {4 A x \left (\tan ^{13}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{a}+\frac {284 A x \left (\tan ^{8}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{a}+\frac {20 A x \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{a}+\frac {4 A x}{a}+\frac {336 A x \left (\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{a}+\frac {56 A x \left (\tan ^{11}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{a}+\frac {120 A x \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{a}+\frac {1448 A \left (\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{3 a d}+\frac {5668 A \left (\tan ^{8}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{15 a d}+\frac {668 A \left (\tan ^{9}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{3 a d}+\frac {120 A x \left (\tan ^{10}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{a}+\frac {336 A x \left (\tan ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{a}+\frac {8552 A \left (\tan ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{15 a d}+\frac {800 A \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{3 a d}+\frac {6248 A \left (\tan ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{15 a d}+\frac {56 A x \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{a}+\frac {328 A \left (\tan ^{10}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{3 a d}+\frac {512 A \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{a d}+\frac {204 A x \left (\tan ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{a}}{\left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )^{4} a^{2} \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{5}}\) | \(520\) |
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Leaf count of result is larger than twice the leaf count of optimal. 225 vs. \(2 (97) = 194\).
Time = 0.27 (sec) , antiderivative size = 225, normalized size of antiderivative = 2.18 \[ \int \frac {\sin ^3(c+d x) (A-A \sin (c+d x))}{(a+a \sin (c+d x))^3} \, dx=\frac {15 \, A \cos \left (d x + c\right )^{4} + {\left (60 \, A d x + 149 \, A\right )} \cos \left (d x + c\right )^{3} - 240 \, A d x + {\left (180 \, A d x - 103 \, A\right )} \cos \left (d x + c\right )^{2} - 3 \, {\left (40 \, A d x + 81 \, A\right )} \cos \left (d x + c\right ) + {\left (15 \, A \cos \left (d x + c\right )^{3} - 240 \, A d x + 2 \, {\left (30 \, A d x - 67 \, A\right )} \cos \left (d x + c\right )^{2} - 3 \, {\left (40 \, A d x + 79 \, A\right )} \cos \left (d x + c\right ) + 6 \, A\right )} \sin \left (d x + c\right ) - 6 \, A}{15 \, {\left (a^{3} d \cos \left (d x + c\right )^{3} + 3 \, a^{3} d \cos \left (d x + c\right )^{2} - 2 \, a^{3} d \cos \left (d x + c\right ) - 4 \, a^{3} d + {\left (a^{3} d \cos \left (d x + c\right )^{2} - 2 \, a^{3} d \cos \left (d x + c\right ) - 4 \, a^{3} d\right )} \sin \left (d x + c\right )\right )}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 2290 vs. \(2 (100) = 200\).
Time = 12.94 (sec) , antiderivative size = 2290, normalized size of antiderivative = 22.23 \[ \int \frac {\sin ^3(c+d x) (A-A \sin (c+d x))}{(a+a \sin (c+d x))^3} \, dx=\text {Too large to display} \]
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Leaf count of result is larger than twice the leaf count of optimal. 543 vs. \(2 (97) = 194\).
Time = 0.32 (sec) , antiderivative size = 543, normalized size of antiderivative = 5.27 \[ \int \frac {\sin ^3(c+d x) (A-A \sin (c+d x))}{(a+a \sin (c+d x))^3} \, dx=\frac {2 \, {\left (3 \, A {\left (\frac {\frac {105 \, \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} + \frac {189 \, \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}} + \frac {200 \, \sin \left (d x + c\right )^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}} + \frac {160 \, \sin \left (d x + c\right )^{4}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{4}} + \frac {75 \, \sin \left (d x + c\right )^{5}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{5}} + \frac {15 \, \sin \left (d x + c\right )^{6}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{6}} + 24}{a^{3} + \frac {5 \, a^{3} \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} + \frac {11 \, a^{3} \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}} + \frac {15 \, a^{3} \sin \left (d x + c\right )^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}} + \frac {15 \, a^{3} \sin \left (d x + c\right )^{4}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{4}} + \frac {11 \, a^{3} \sin \left (d x + c\right )^{5}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{5}} + \frac {5 \, a^{3} \sin \left (d x + c\right )^{6}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{6}} + \frac {a^{3} \sin \left (d x + c\right )^{7}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{7}}} + \frac {15 \, \arctan \left (\frac {\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1}\right )}{a^{3}}\right )} + A {\left (\frac {\frac {95 \, \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} + \frac {145 \, \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}} + \frac {75 \, \sin \left (d x + c\right )^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}} + \frac {15 \, \sin \left (d x + c\right )^{4}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{4}} + 22}{a^{3} + \frac {5 \, a^{3} \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} + \frac {10 \, a^{3} \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}} + \frac {10 \, a^{3} \sin \left (d x + c\right )^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}} + \frac {5 \, a^{3} \sin \left (d x + c\right )^{4}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{4}} + \frac {a^{3} \sin \left (d x + c\right )^{5}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{5}}} + \frac {15 \, \arctan \left (\frac {\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1}\right )}{a^{3}}\right )}\right )}}{15 \, d} \]
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Time = 0.31 (sec) , antiderivative size = 113, normalized size of antiderivative = 1.10 \[ \int \frac {\sin ^3(c+d x) (A-A \sin (c+d x))}{(a+a \sin (c+d x))^3} \, dx=\frac {2 \, {\left (\frac {30 \, {\left (d x + c\right )} A}{a^{3}} + \frac {15 \, A}{{\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 1\right )} a^{3}} + \frac {60 \, A \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} + 285 \, A \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 505 \, A \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 335 \, A \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 79 \, A}{a^{3} {\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1\right )}^{5}}\right )}}{15 \, d} \]
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Time = 16.24 (sec) , antiderivative size = 261, normalized size of antiderivative = 2.53 \[ \int \frac {\sin ^3(c+d x) (A-A \sin (c+d x))}{(a+a \sin (c+d x))^3} \, dx=\frac {4\,A\,x}{a^3}-\frac {\left (20\,A\,\left (c+d\,x\right )-\frac {4\,A\,\left (75\,c+75\,d\,x+30\right )}{15}\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6+\left (44\,A\,\left (c+d\,x\right )-\frac {4\,A\,\left (165\,c+165\,d\,x+150\right )}{15}\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5+\left (60\,A\,\left (c+d\,x\right )-\frac {4\,A\,\left (225\,c+225\,d\,x+320\right )}{15}\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4+\left (60\,A\,\left (c+d\,x\right )-\frac {4\,A\,\left (225\,c+225\,d\,x+385\right )}{15}\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3+\left (44\,A\,\left (c+d\,x\right )-\frac {4\,A\,\left (165\,c+165\,d\,x+367\right )}{15}\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+\left (20\,A\,\left (c+d\,x\right )-\frac {4\,A\,\left (75\,c+75\,d\,x+205\right )}{15}\right )\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )+4\,A\,\left (c+d\,x\right )-\frac {4\,A\,\left (15\,c+15\,d\,x+47\right )}{15}}{a^3\,d\,{\left (\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )+1\right )}^5\,\left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+1\right )} \]
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